4+(8/x-3)=(-9/((x-3)^2))

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Solution for 4+(8/x-3)=(-9/((x-3)^2)) equation:



4+(8/x-3)=(-9/((x-3)^2))
We move all terms to the left:
4+(8/x-3)-((-9/((x-3)^2)))=0
Domain of the equation: x-3)!=0
x∈R
Domain of the equation: ((x-3)^2)))!=0
x∈R
We get rid of parentheses
8/x-((-9/((x-3)^2)))-3+4=0
We calculate fractions
(8*((x-3)^2))))/(x*((x-3)^2))))+(-((-9*x)/(x*((x-3)^2))))-3+4=0
We can not solve this equation

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